2x^2+8x=-18x-60

Solution for 2x^2+8x=-18x-60 equation:

2x^2+8x=-18x-60

We move all terms to the left:

2x^2+8x-(-18x-60)=0

We get rid of parentheses

2x^2+8x+18x+60=0

We add all the numbers together, and all the variables

2x^2+26x+60=0

a = 2; b = 26; c = +60;
Δ = b2-4ac
Δ = 262-4·2·60
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*2}=\frac{-40}{4}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*2}=\frac{-12}{4}
=-3
$